Answer
$\cot$$^{2}$ 135$^{\circ}$ - $\sin$ 30$^{\circ}$ + 4($\tan$ 45$^{\circ}$) = $\frac{9}{2}$
Work Step by Step
$\cot$$^{2}$ 135$^{\circ}$ - $\sin$ 30$^{\circ}$ + 4($\tan$ 45$^{\circ}$)
$\cot$ 135$^{\circ}$ = $\cot$ 45$^{\circ}$(In Quadrant II) = -1
$\sin$ 30$^{\circ}$ = $\frac{1}{2}$
$\tan$ 45$^{\circ}$ = 1
Therefore:
= (-1)$^{2}$ - $\frac{1}{2}$ + 4
= 1 - $\frac{1}{2}$ + 4
= $\frac{2 - 1 + 8}{2}$
= $\frac{9}{2}$
$\cot$$^{2}$ 135$^{\circ}$ - $\sin$ 30$^{\circ}$ + 4($\tan$ 45$^{\circ}$) = $\frac{9}{2}$
