Answer
$\sum ^{10}_{k=1}\left( 3k-1\right) $
Work Step by Step
$2+5+8+\ldots +29=\left( 3\times 1-1\right) +\left( 3\times 2-1\right) +\left( 3\times 3-1\right) +\ldots +\left( 3\times 10-1\right) =\sum ^{10}_{k=1}\left( 3k-1\right) $
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