Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 68

Answer

$\sum ^{10}_{k=1}\left( 3k-1\right) $

Work Step by Step

$2+5+8+\ldots +29=\left( 3\times 1-1\right) +\left( 3\times 2-1\right) +\left( 3\times 3-1\right) +\ldots +\left( 3\times 10-1\right) =\sum ^{10}_{k=1}\left( 3k-1\right) $
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