Answer
$31$
Work Step by Step
$\sum ^{5}_{k=1}2^{k-1}=\sum ^{4}_{i=0}2^{i}=2^{0}+2^{1}+2^{2}+2^{3}+2^{4}=1+2+4+8+16=31$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 53
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