Answer
$90$
Work Step by Step
$\sum ^{12}_{i=4}10=\sum ^{12-3}_{i=4-3}10=\sum ^{9}_{i=1}10=9\times 10=90$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 52
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
