Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 67

Answer

$\sum ^{25}_{k=1}2k$

Work Step by Step

$2+4+6+\ldots +50=1\times 2+2\times 2+3\times 2+\ldots +25\times 2=\sum ^{25}_{k=1}2k$
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