Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 38

Answer

$A(n)=(\frac{1}{n})^{(-1^n)}$

Work Step by Step

Ok so we start with the simply 1,2,3,4,5,6,7,8,9 sequence or $n$. Then we half to take the even terms and make them their reciprocals. To do this we add an element of $(-1^{(n)})$ to the sequence. And lets do (1/n) to the power this. That's our answer!
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