Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 56

Answer

$15550$

Work Step by Step

$\sum ^{100}_{k=1}\left( 3k+4\right) =\sum ^{100}_{k=1}3k+\sum ^{100}_{k=1}4=\dfrac {3n\left( n+1\right) }{2}+4n=\dfrac {3\times 100\times 101}{2}+4\times 100=15550$ Also we get same result when using graphing calculator (shown in picture).
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