Answer
$\dfrac {11}{6}$
Work Step by Step
$\sum ^{3}_{k=1}\dfrac {1}{k}=\dfrac {1}{1}+\dfrac {1}{2}+\dfrac {1}{3}=\dfrac {6+3+2}{6}=\dfrac {11}{6}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 851: 49
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