Answer
$g^{-1}(x)=\frac{3-x}{x-2}$
Work Step by Step
$g(x)=\frac{2x+3}{x+1}$,
$y=\frac{2x+3}{x+1}$,
$x=\frac{2y+3}{y+1}$,
$y=\frac{3-x}{x-2}$,
$g^{-1}(x)=\frac{3-x}{x-2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 58
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