Answer
$4$
Work Step by Step
We know that $\lim\limits_{x \to a} k(x)=k(a)$, where $a$ is a constant.
Thus, we have:
$\lim\limits_{x \to 2} (3x-4)^2=(3x)^2+(4)^2-2(3x)(4) \\=9(2)^2+16-2(3 \cdot 2)(4) \\=36+16-48 \\=4$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 22
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