Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.2 Algebra Techniques for Finding Limits - 13.2 Assess Your Understanding - Page 903: 13

Answer

$80$

Work Step by Step

Use the limit properties: $(1) \ \lim\limits_{x \to a} l(x)=l (a) \\ (2) \lim\limits_{x \to a} k(x) l(x)=\lim\limits_{x \to a} k(x) \cdot \lim\limits_{x \to a} l(x)$ where $a$ is a constant. $\lim\limits_{x \to 2} (5x^4)=\lim\limits_{x \to 2} (5) \cdot \lim\limits_{x \to 2} (x^4) \\=(5)(2)^4\\=(5)(16)\\=80$
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