Answer
$28$
Work Step by Step
Use the limit properties:
$(1) \lim\limits_{x \to a} (px \pm qx)=\lim\limits_{x \to a} p(x) \pm \lim\limits_{x \to a} qx \\ (2) \ \lim\limits_{x \to a} l(x)=l (a) $
where $a$ is a constant.
$\lim\limits_{x \to 2} (8x^2-4)=\lim\limits_{x \to 2} (8x^2)-\lim\limits_{x \to 2} (4)\\ =8(2)^2-4\\=8(4)-4\\=32-4\\=28$
