Answer
$-13$
Work Step by Step
Use the limit properties:
$(1) \ \lim\limits_{x \to a} l(x)=l (a) \\ (2) \lim\limits_{x \to a} (px \pm q)=\lim\limits_{x \to a} p(x) \pm \lim\limits_{x \to a} q$
where $a$ is a constant.
$\lim\limits_{x \to 3} (2x-5) =\lim\limits_{x \to 3}(2x) -\lim\limits_{x \to 3} 5 \\ =2(3)-5\\=2-15 \\=-13$
