Answer
$2(x+1)(4x-1)$
Work Step by Step
We have
$ 8x^2 + 6x - 2=2(4x^2+3x-1)=2(4x^2+4x-x-1)$.
By grouping the first two terms and the second two terms, and then taking common factors, we have
$$
2(4x^2+4x-x-1)=2(4x(x+1)-(x+1))=2(x+1)(4x-1)
.$$