Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 45

$(x-2)(x-8)$

To factor a second-degree polynomial $x^2 - 10x + 16$, we have to find integers whose product is $16$ and whose sum is $-10$. That is, we have $-2$ and $-8$ where $-2-8=-10$ and $-2\times (-8)=16$. Thus: $$ x^2 - 10x + 16=(x-2)(x-8) .$$