Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 61

Answer

$(x+2)(3x-4)$

Work Step by Step

First, for the polynomial $3x^2 + 2x - 8$, we write $$ 3x^2 + 2x - 8=3x^2 + 6x -4x- 8 .$$ By grouping the first two terms and the second two terms and then taking common factors, we have $$ 3x^2 + 6x -4x- 8=3x(x+2)-4(x+2)=(x+2)(3x-4) .$$
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