Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 91

Answer

$y^2(y+5)(y+6)$

Work Step by Step

For the polynomial $y^4 + 11y^3 + 30y^2=y^2(y^2 +11y +30)$, we have to find integers whose product is $30$ and whose sum is $11$. That is, we have $5$ and $6$, where $6+5=11$ and $5\times (6)=30$. Thus $$ y^2(y^2 +11y +30)=y^2(y+5)(y+6) .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.