Answer
$2(x+1)(3x+1)$
Work Step by Step
We have
$6x^2 + 8x + 2=2(3x^2+4x+1)=2(3x^2+3x+x+1)$
By grouping the first two terms and the second two terms, and then taking common factors, we have
$$
2(3x^2+3x+x+1)=2(3x(x+1)+(x+1))=2(x+1)(3x+1)
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 95
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
