Answer
$3(1-3x)(1+3x)$
Work Step by Step
The polynomial $1-(3x)^2$ is a difference of the two squares $(3x)^2$ and $1^2$. That is, by using the fact that $a^2-b^2=(a-b)(a+b)$, we have
$$
3-27x^2=3(1-(3x)^2)=3(1-3x)(1+3x)
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 78
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