Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 22

Answer

$9(2x-1)(2x+1) $

Work Step by Step

By using the difference of two squares $a^2-b^2=(a-b)(a+b)$, we have $$ 36x^2 - 9=(6x-3)(6x+3)=3(2x-1)(3)(2x+1)\\ =9(2x-1)(2x+1) .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.