Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.5 - Determinants and Cramer's Rule - Exercise Set - Page 945: 9

Answer

$-\dfrac{7}{16}$

Work Step by Step

The general formula to calculate the determinant of a $2 \times 2$ matrix which has 2 rows and 2 columns is $D=\begin{vmatrix}a&b\\c&d\end{vmatrix}=ad-bc$ Now, $D=\begin{vmatrix}\frac{1}{2}&\frac{1}{2}\\\frac{1}{8}&\frac{-3}{4}\end{vmatrix}=\frac{-3}{8}-\frac{1}{16}=-\dfrac{7}{16}$
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