Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 44

Answer

The systems of equations are $x+y=2$ and $x-y=8$ and the solution to the equations is $\left( x,y \right)=\left( 5,-3 \right)$.

Work Step by Step

Let us assume the two numbers are x and y. And the sum of the numbers is 2. This gives the equation as: $x+y=2$ And the difference between the numbers is −1. This gives the equation as: $x-y=8$ Add equations $x+y=2$ and $x-y=8$ to obtain: $\begin{align} & x+y+x-y=2+8 \\ & 2x=10 \\ & x=5 \end{align}$ Substitute the value of x in equation (I) $\begin{align} & 5+y=2 \\ & y=-3 \end{align}$ Hence, the system of equations are $x+y=2$ and $x-y=8$ and the solution to the system of equations is $\left( x,y \right)=\left( 5,-3 \right)$.
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