Answer
The required value is $x=3,y=1$
Work Step by Step
We have to multiply the second equation with 2 and then subtract this from the first equation:
$\begin{align}
& 4x+3y-2\left( 2x-5y \right)=15-2\left( 1 \right) \\
& 4x+3y-4x+10y=15-2 \\
& 13y=13 \\
& y=1
\end{align}$
Substitute the value of $y=1$ in the second equation:
$\begin{align}
& 2x-5\left( 1 \right)=1 \\
& 2x=1+5 \\
& 2x=6 \\
& x=3
\end{align}$
Thus, the value of $x=3$ and $y=1$.
