Answer
The required value is $x=3,y=0$
Work Step by Step
We add both equations to obtain,
$\begin{align}
& 2x+3y+\left( 2x-3y \right)=6+6 \\
& 4x=6+6 \\
& 4x=12 \\
& x=3
\end{align}$
Substitute the value of $x=3$ in the first equation and solve for y as follows:
$\begin{align}
& 2\left( 3 \right)+3y=6 \\
& 6+3y=6 \\
& 3y=0 \\
& y=0
\end{align}$
Thus, the value of $x=3$ and .
