Answer
The required value is $x=2,y=-1$
Work Step by Step
We have to multiply the first equation with 2 and then subtract this from the second equation:
$\begin{align}
& 6x+5y-2\left( 3x-7y \right)=7-2\left( 13 \right) \\
& 6x+5y-6x+14y=7-26 \\
& 19y=-19 \\
& y=-1
\end{align}$
Substitute the value of $y=-1$ in the first equation to obtain,
$\begin{align}
& 3x-7\left( -1 \right)=13 \\
& 3x+7=13 \\
& 3x=6 \\
& x=2
\end{align}$
Thus, the value of $x=2$ and $y=-1$.
