Answer
$(-2,1)$
Work Step by Step
Here, we have $6y=8+x \implies x=6y-8$
Now, $2(6y-8)+5y=1$
This gives: $12y-16+5y=1 $ or, $y=1$
Thus, $x=6(1)-8=-2$
Solution is: $(x,y)=(-2,1)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 7 - Section 7.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 818: 14
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