Answer
The required value is $x=4,y=1$
Work Step by Step
We add both equations to obtain,
$\begin{align}
& \left( 3x+2y \right)+\left( 3x-2y \right)=14+10 \\
& 3x+3x+2y-2y=24 \\
& 6x=4 \\
& x=4
\end{align}$
Substitute the value of $x=4$ in the first equation to obtain,
$\begin{align}
& 3\left( 4 \right)+2y=14 \\
& 12+2y=14 \\
& 2y=2 \\
& y=1
\end{align}$
Thus, the value of $x=4$ and $y=1$.
