Answer
The required value is $\left\{ \left( 1,4 \right) \right\}$
Work Step by Step
Multiply the second equation by $2$ and then add that to the first equation to obtain:
$\begin{align}
& 2\left( 4x+y \right)+\left( 3x-2y \right)=2\left( 8 \right)+\left( -5 \right) \\
& 8x+2y+3x-2y=16-5 \\
& 11x=11 \\
& x=1
\end{align}$
Substitute the value of $x$ in the first equation and solve for y as follows:
$\begin{align}
& 3-2y=-5 \\
& -2y=-8 \\
& y=4
\end{align}$
Thus, the solution set is $\left\{ \left( 1,4 \right) \right\}$.
