Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.5 - Trigonometric Equations - Exercise Set - Page 703: 7

Answer

$\frac{5\pi }{12}$ is the solution of the given equation.

Work Step by Step

We know that according to the ratio table of trigonometry, the value of $\tan (2*\frac{5\pi }{12})$ is given as $-\frac{\sqrt{3}}{3}$. $\begin{align} & \tan 2x=-\frac{\sqrt{3}}{3} \\ & \tan 2.\frac{5\pi }{12}=-\frac{\sqrt{3}}{3} \\ & \tan \frac{5\pi }{6}=-\frac{\sqrt{3}}{3} \\ & -\frac{\sqrt{3}}{3}=-\frac{\sqrt{3}}{3} \end{align}$ Thus, $\tan 2x=-\frac{\sqrt{3}}{3}$ is true.
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