Answer
$\frac{\pi }{6}$ is not a solution of the given equation.
Work Step by Step
We know that according to the ratio table of trigonometry, the value of $\sin \frac{\pi }{6}$ is given as $\frac{1}{2}$.
$\begin{align}
& \sin x=\frac{\sqrt{3}}{2} \\
& \sin \frac{\pi }{6}=\frac{\sqrt{3}}{2} \\
& \frac{1}{2}=\frac{\sqrt{3}}{2}
\end{align}$
Thus, $\sin x=\frac{\sqrt{3}}{2}$ is false.
