Answer
The solutions of the equation are $x=\frac{\pi }{3}+n\pi $, where n is any integer.
Work Step by Step
The x in $\tan x=\sqrt{3}$. Because $\tan \frac{\pi }{3}=\sqrt{3}$, and the solution of $\tan x=\sqrt{3}$ in [0, $\pi $ ) is:
$x=\frac{\pi }{3}$
The period of the tangent function is $\pi $, and the solutions are given by:
$x=\frac{\pi }{3}+n\pi $, where n is any integer.
