Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 98

Answer

The exact value of the provided expression is $\frac{2\pi }{3}$.

Work Step by Step

Let us assume $\theta ={{\cos }^{-1}}\left( -\frac{1}{2} \right)$. Then, we have $\cos \theta =\left( -\frac{1}{2} \right)$ We know that for the cosine function, the interval for the angle is $\left[ 0,\pi \right]$. Therefore, the only angle that satisfies $\cos \theta =\left( -\frac{1}{2} \right)$ is $\left( \frac{2\pi }{3} \right)$. Hence, $\theta =\frac{2\pi }{3}$ and the exact value of the given expression is ${{\cos }^{-1}}\left( -\frac{1}{2} \right)=\frac{2\pi }{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.