Answer
$\dfrac{\pi}{3}$
Work Step by Step
We have $ \theta= \sin [\sin^{-1} \dfrac{\pi}{3}]$
$\implies \theta=\dfrac{\pi}{3}$
Because the trigonometric functions sine and arcsine will "cancel out".
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Review Exercises - Page 646: 110
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