Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 646: 107

Answer

The exact value of the provided expression is $-\frac{3}{4}$.

Work Step by Step

Let us assume $\theta ={{\sin }^{-1}}\left( -\frac{3}{5} \right)$. Then, $\sin \theta =-\frac{3}{5}$ As we know that $\sin \theta $ is negative, $\theta $ lies in the fourth quadrant. Now, by using the Pythagorean theorem: $\begin{align} & {{r}^{2}}={{x}^{2}}+{{y}^{2}} \\ & {{5}^{2}}={{x}^{2}}+{{\left( -3 \right)}^{2}} \\ & x=\sqrt{25-9} \\ & x=4 \end{align}$ Then, the value of the given expression is $\begin{align} & \tan \left[ {{\sin }^{-1}}\left( -\frac{3}{5} \right) \right]=\tan \theta \\ & =\frac{y}{x} \\ & =-\frac{3}{4} \end{align}$
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