Answer
$\approx 5.39$ units
Work Step by Step
Use the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ to obtain:
$d=\sqrt{(-2-3)^2+(-6-(-4))^2}
\\d=\sqrt{(-5)^2+(-6+4)^2}
\\d=\sqrt{25+(-2)^2}
\\d=\sqrt{25+4}
\\d=\sqrt{29}
\\d \approx 5.39$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 7
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