Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 68

See graph. $(0,-3)$ and $(3,0)$. See explanations.

Step 1. See graph. Step 2. We can find the intersections as $(0,-3)$ and $(3,0)$. Step 3. With the original equations, plug-in the coordinates; we have $(0)^2+(-3)^2=9, (0)-(-3)=3$ and $(3)^2+(0)^2=9, (3)-(0)=3$