Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 18

Answer

$d\approx 1.41$

Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $x_2, y_2)$ can be found using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Solve for the distance between the two points using the formula above to obtain: $d=\sqrt{(-\frac{1}{4}-\frac{3}{4})^2+(-\frac{1}{7}-\frac{6}{7})^2} \\d=\sqrt{(-\frac{4}{4})^2+(-\frac{7}{7})^2} \\d=\sqrt{(-1)^2+(-1)^2} \\d=\sqrt{1+1} \\d=\sqrt{2} \\d\approx 1.41$
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