Answer
$(x+6)^2+(y-3)^2=49$
$C(-6,3), r=7$
See graph.
Work Step by Step
Step 1. From the given equation $x^2+y^2+12x-6y-4=0$, we have $(x^2+12x+36)+(y^2-6y+9)=36+9+4$ and $(x+6)^2+(y-3)^2=49$
Step 2. We can identify the center and radius of the circle as $C(-6,3), r=7$
Step 3. See graph.
