Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 38

$(x+5)^2+(y+3)^2=5$

RECALL: The standard equation of a circle whose center is at $(h, k)$ and has a radius of $r$ units is: $(x-h)^2 + (y-k)^2 = r^2$ The given circle has its center at $(-5, -3)$ and a radius of $\sqrt5$ units. Thus, the standard form of the circle's equation is: $(x-(-5))^2+(y-(-3))^2=(\sqrt5)^2 \\(x+5)^2+(y+3)^2=5$