Answer
$(x+4)^2+(y-1)^2=25$
$C(-4,1), r=5$
See graph.
Work Step by Step
Step 1. From the given equation $x^2+y^2+8x-2y-8=0$, we have $(x^2+8x+16)+(y^2-2y+1)=16+1+8$ and $(x+4)^2+(y-1)^2=25$
Step 2. We can identify the center and radius of the circle as $C(-4,1), r=5$
Step 3. See graph.
