Answer
$log_2[x(3x-2)^4]$
Work Step by Step
$8log_2\sqrt {3x-2}-log_2(\frac{4}{x})+log_24=log_2[\frac{(3x-2)^{8/2}}{1}\cdot \frac{x}{4}\cdot 4]=log_2[x(3x-2)^4]$
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