Answer
$42$
Work Step by Step
We know that $\log_a {x}+\log_a {y}=\log_a {(x\cdot y)}$.
Hence,
$5^{\log_5{6}+\log_5 {7}}=5^{\log_5 {(6\cdot 7)}}=5^{\log_5{42}}$.
We also know that $a^{\log_a {x}}=x$.
Thus,
$5^{\log_5 {42}}=42$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 26
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