Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 11

Answer

(b)

Work Step by Step

The answer is (b) because $e^{xln2}=e^{ln(2^x)}=2^x$
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