Answer
$2$
Work Step by Step
We know that $\log_a {x}+\log_a {y}=\log_a {(x\cdot y)}$.
Hence,
$\log_6 {4}+\log_6 {9}
\\=\log_6{(4\cdot 9)}
\\=\log_6{36}
\\=log_6 {(6^2)}$.
We know that $\log_a {a^x}=x$.
Thus,
$\log_6 {6^2}=2$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 305: 20
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