Answer
$ 3logx+\frac{1}{2}log(x+1)-2log(x-2)$
Work Step by Step
$log[\frac{x^3\sqrt {x+1}}{(x-2)^2}]=log[\frac{x^3(x+1)^{1/2}}{(x-2)^2}]=logx^3+log(x+1)^{1/2}-log(x-2)^2=3logx+\frac{1}{2}log(x+1)-2log(x-2)$
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