Answer
$\sqrt {x^2y} = xy^{\frac{1}{2}} $
Work Step by Step
$\sqrt {x^2y} = (x^2y)^{\frac{1}{2}} = x^{2\times\frac{1}{2}}y^{\frac{1}{2}} = x^{1}y^{\frac{1}{2}} = xy^{\frac{1}{2}} $
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 70
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