Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 59

Answer

$\sqrt {(x+9)^2} = x+9$

Work Step by Step

Because x is a positive number, $x+9$ is also a positive number. Therefore, $\sqrt {(x+9)^2} = x+9$.
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