Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 51

Answer

$\sqrt[3] {\frac{27}{8}} = \frac{3}{2}$

Work Step by Step

$\sqrt[3] {\frac{27}{8}} $ By the formula on page 11, $\sqrt[3] {\frac{27}{8}} = \frac{\sqrt[3] {27}}{\sqrt[3] 8} = \frac{\sqrt[3] {3^3}}{\sqrt[3] {2^3}} = \frac{3}{2}$.
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