Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 16: 52

Answer

$\sqrt[3] {8\times64} = 8$

Work Step by Step

By the formula on page 11, $\sqrt[3] {8\times64} = \sqrt[3] {8} \times \sqrt[3] {64} = \sqrt[3] {2^3} \times \sqrt[3] {4^3} = 2 \times 4 = 8$.
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