Answer
$(\frac{x^2y^{-1}z^0}{xyz})^2 = \frac{x^2}{y^4z^2}$
Work Step by Step
By the formulas given on page eight and nine,
$(\frac{x^2y^{-1}z^0}{xyz})^2 = \frac{(x^2y^{-1})^2}{(xyz)^2} = \frac{x^4y^{-2}}{x^2y^2z^2} = x^{4-2}y^{(-2)-2}z^{0-2} = x^2y^{-4}z^{-2} =x^2\frac{1}{y^4} \frac{1}{z^2} = \frac{x^2}{y^4z^2}$.
